Yasmin Finney is set to play Rose in the 60th-anniversary specials of Doctor Who later this year. The character shares her namesake with Rose Tyler, played by Billie Piper, the first companion to travel with the Doctor in the revived era. Typically, the Doctor Who fandom ignited with speculation over Finney’s identity, as the name could not have been a coincidence. Now, we know how the character will fit into the story – as Donna’s daughter, Rose Noble.
“Welcome to the Doctor Who family, Rose Noble,” the show’s Twitter account shared in a post. “Wishing a very happy birthday to Yasmin Finney, whose character Rose is the daughter of companion Donna Noble (played by Catherine Tate) and Shaun Temple (Karl Collins).”
“So, the question is, what happens when Rose meets one of her mum’s oldest friends? It is a mystery for now, but what we do know is that just like her mother, Rose stumbles across something alien – and from that point her seemingly ordinary family is never quite the same…” a second tweet on the account reads.
There we have it, and the inclusion of Donna’s daughter, with Rose’s name, brings to mind the final scene from Catherine Tate’s Christmas Special debut (all the way back in 2006), as the Doctor revealed Rose’s name to the jilted bride.
It would suggest that, despite Donna losing her memory in the Series 4 finale, she retained some ‘DoctorDonna’ knowledge of her adventures with the Time Lord. As for how Donna will fit into the 60th-anniversary specials, fans are still in the dark.
In a titles reveal trailer back in May, Tate’s character can be heard asking why “this face” came back, referring to Tennant’s Tenth-turned-Fourteenth incarnation.
Annoyingly, we have another few months to wait for the answers, though the specials will be worth it. Doctor Who is available to stream via the BBC iPlayer, with classic episodes available on Britbox. What are you most excited to see from the future of the series? Let us know your thoughts in the comments below!
Doctor Who has an art exhibition launching in November.